Which of the following procedures would be be | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The starting material is $4$-chlorotoluene. The final product is $4$-chloro-$2$-bromo-$5$-nitrobenzoic acid.Step $1$: Electrophilic aromatic subst

Vedclass · Accepted Answer

$(i) \ Br_2 + FeBr_3$$(ii) \ KMnO_4$ and heat$(iii) \ HNO_3$ and $H_2SO_4$

Vedclass · Answer

(A) The starting material is $4$-chlorotoluene. The final product is $4$-chloro-$2$-bromo-$5$-nitrobenzoic acid.Step $1$: Electrophilic aromatic substitution with $Br_2$ and $FeBr_3$ introduces a bromine atom at the ortho position relative to the methyl group (due to the activating nature of the $-CH_3$ group).Step $2$: Oxidation of the methyl group using $KMnO_4$ and heat converts the $-CH_3$ group into a carboxylic acid group $(-COOH)$.Step $3$: Nitration using $HNO_3$ and $H_2SO_4$ introduces a nitro group $(-NO_2)$ at the position ortho to the $-COOH$ group,which is the meta position relative to the $-Cl$ and $-Br$ substituents,following the directing effects of the existing groups.

Which of the following procedures would be best for achieving the following reaction?

Similar Questions

Which order is correct for the decreasing reactivity toward ring monobromination of the following compounds:
$I. \, C_6H_5CH_3$
$II. \, C_6H_5COOH$
$III. \, C_6H_6$
$IV. \, C_6H_5NO_2$

The major product of the following reaction is:

Arrange the following compounds in the decreasing order of their reactivity towards electrophilic substitution reaction: Aniline $(I)$,Benzene $(II)$,and Nitrobenzene $(III)$.

From the following compounds, choose the one which is not aromatic.

$C_6H_6 + 3Cl_2 \xrightarrow{UV \ \text{light}} \text{Product}$. In the above reaction,the product is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module